JEE Main · 2021 · 22 Jul 2021 · Shift 2 · Equilibrium

Value of

K_{p}

for the equilibrium reaction

N X_{2} O X_{4} (g) 2 NO X_{2} (g)

at 288 K is 47.9. The

K_{c}

for this reaction at same temperature is ______. (Nearest integer)
(

R = 0.083 L bar K^{- 1} mol^{- 1}

)

Answer: 2

Solution

For a gas phase equilibrium

K_{p} = K_{c} (R T)^{Δ n}

, where

Δ n

is the change in the number of moles of gas. Here

Δ n = 2 - 1 = 1

, so

K_{c} = \frac{K _{p}}{R T} = \frac{47.9}{0.083 \times 288} = \frac{47.9}{23.90}

This gives

K_{c} = 2.004

, so to the nearest integer

K_{c} = 2

JEE Main · 2021 · 22 Jul 2021 · Shift 2 · Integer answer