The function is not differentiable at exactly:
- (A)three points
- (B)four points
- (C)two points✓ Correct
- (D)one point
Answer: (C)
Solution
The factor has simple zeros at and , where has corners. The exponent is a perfect square, so is smooth and is differentiable everywhere and never zero. The product therefore fails to be differentiable only at and , that is, at two points.
JEE Main · 2021 · 31 Aug 2021 · Shift 1 · Single correct option