A triangular plate is shown. A force F=4i^−3j^ is applied at point P. The torque at point P with respect to point 'O' and 'Q' are:
(A)15+203,15−203
(B)−15−203,15−203✓ Correct
(C)−15+203,15+203
(D)15−203,15+203
Answer: (B)
Solution
Place O at the origin and Q at (10,0). The triangle is equilateral of side 10, so P sits at (5,53). About O the position vector of P is r=5i^+53j^, and for planar vectors (ai^+bj^)×(ci^+dj^)=(ad−bc)k^:
τO=(5i^+53j^)×(4i^−3j^)=(−15−203)k^
About Q the position vector of P is r=−5i^+53j^:
τQ=(−5i^+53j^)×(4i^−3j^)=(15−203)k^
The torques about O and about Q are −15−203 and 15−203 respectively.
JEE Main · 2021 · 17 Mar 2021 · Shift 1 · Single correct option