JEE Main · 2021 · 17 Mar 2021 · Shift 1 · Hydrocarbons

WhatsApp Email

In the above reaction, 3.9 g of benzene on nitration gives 4.92 g of nitrobenzene. The percentage yield of nitrobenzene in the above reaction is ______ %
(Round off to the nearest integer).
(Given atomic mass : C: 12.0u, H:1.0u, O:16.0u, N:14.0u)

Answer: 80

Solution

Nitration replaces one ring hydrogen of benzene by a nitro group, so at best one mole of benzene yields one mole of nitrobenzene. Benzene has molar mass

78

g mol

^{- 1}

and nitrobenzene

123

g mol

^{- 1}

, so

3.9

g of benzene is

0.05

mol and a complete conversion would give

0.05 \times 123 = 6.15

g of nitrobenzene. The mass obtained is

4.92

g, so

yield = \frac{4.92}{6.15} \times 100

and the percentage yield of nitrobenzene is

80%

JEE Main · 2021 · 17 Mar 2021 · Shift 1 · Integer answer

Practise more: all JEE Main PYQs on Hydrocarbons →

More JEE Main questions on Hydrocarbons

Identify A in the following reaction.
JEE Main 2026View solution →
Given below are two statements :

Statement I : Benzene is nitrated to give nitrobenzene, which on further treatment with
$CH_{3} COCl / AlCl_{3}$ will give
JEE Main 2026View solution →
As compared with chlorocyclohexane, which of the following statements correctly apply to chlorobenzene?
A. The magnitude of negative charge is more on chlorine atoms
B. The $C - Cl$ bond has partial double bond character
C. $C - Cl$ bond is les …
JEE Main 2026View solution →
The cycloalkane ( X ) on bromination consumes one mole of bromine per mole of ( X ) and gives the product ( Y ) in which $C : Br$ ratio is $3 : 1$ . The percentage of bromine in the product $(Y)$ is
____ %. (Nearest integer)
(Given : Molar mass …
JEE Main 2026View solution →
The dibromo compound [P] (molecular formula: $C_{9} H_{10} Br_{2}$ ) when heated with excess sodamide followed by treatment with dilute HCl gives [Q]. On warming [Q] with mercuric sulphate and dilute sulphuric acid yield [R] which gives positive Iodoform t …
JEE Main 2026View solution →
But-2-yne and hydrogen (one mole each) are separately treated with (i) $Pd / C$ and (ii) $Na /$ liq. $NH_{3}$ to give the products X and Y respectively.

Identify the incorrect statements.
A. $X$ and $Y$ are stereoisomers.
B. Dipole moment of X …
JEE Main 2026View solution →