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JEE Main · 2021 · 01 Sep 2021 · Shift 2 · Chemical Thermodynamics

For the reaction

2 NO_{2} (g) ⇌ N_{2} O_{4} (g)

, when

Δ S = - 176.0 JK^{- 1}

and

Δ H = - 57.8 kJ mol^{- 1}

, the magnitude of

Δ G

at 298 K for the reaction is ______

kJ mol^{- 1}

. (Nearest integer)

Answer: 5

Solution

At constant temperature

Δ G = Δ H - T Δ S

. With

Δ S = - 176.0 \times 1 0^{- 3} kJ K^{- 1}

,

Δ G = - 57.8 - 298 (- 0.176) = - 57.8 + 52.45 = - 5.35 kJ mo l^{- 1}

. The magnitude of

Δ G

is

5 kJ mo l^{- 1}

.

JEE Main · 2021 · 01 Sep 2021 · Shift 2 · Integer answer

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