The area of the region, enclosed by the circle x2+y2=2, which is not common to the region bounded by the parabola y2=x and the straight line y=x, is :
(A)31(12π−1)
(B)31(6π−1)
(C)61(12π−1)✓ Correct
(D)61(24π−1)
Answer: (C)
Solution
The circle x2+y2=2 has area 2π. The small region shared with the loop between y2=x and y=x runs from x=0 to x=1 with area ∫01(x−x)dx=32−21=61. Removing this common part, the required area is 2π−61=612π−1.
JEE Main · 2020 · 07 Jan 2020 · Shift 1 · Single correct option