Arrange the following compounds in increasing order of bond length: methanol, phenol, p-ethoxyphenol
- (A)phenol < methanol < p-ethoxyphenol
- (B)methanol < p-ethoxyphenol < phenol
- (C)methanol < phenol < p-ethoxyphenol
- (D)phenol < p-ethoxyphenol < methanol✓ Correct
Answer: (D)
Solution
The length of the bond depends on how far the oxygen lone pair is drawn into resonance. In phenol the lone pair conjugates with the ring, giving the bond partial double-bond character and shortening it; in -ethoxyphenol the electron-donating ethoxy group raises the ring's electron density and strengthens this resonance, shortening the bond further still. Methanol has no such resonance, so its is a pure single bond and the longest of the three. The increasing order of bond length is thus phenol -ethoxyphenol methanol.
JEE Main · 2020 · 08 Jan 2020 · Shift 1 · Single correct option