Consider the following plots of rate constant versus T1 for four different reactions. Which of the following order is correct for the activation energies of these reactions?
(A)Ec>Ea>Ed>Eb✓ Correct
(B)Eb>Ed>Ec>Ea
(C)Ea>Ec>Ed>Eb
(D)Eb>Ea>Ed>Ec
Answer: (A)
Solution
Taking logarithms of the Arrhenius equation gives lnk=lnA−RTEa, so a plot of lnk against T1 is a line of slope −REa; a steeper downward slope means a larger activation energy. Reading the four lines by steepness gives the activation energies in the order Ec>Ea>Ed>Eb.
JEE Main · 2020 · 08 Jan 2020 · Shift 2 · Single correct option