The rate constant (k) of a reaction is measured at different temperatures (T), and the data are plotted in the given figure. The activation energy of the reaction in kJ mol−1 is: ( R is gas constant)
(A)2R✓ Correct
(B)2/R
(C)R
(D)1/R
Answer: (A)
Solution
Taking logarithms of the Arrhenius equation gives lnk=lnA−REa⋅T1, a straight line of lnk against T1 with slope −REa. The plotted line has slope −2, so −REa=−2 and the activation energy is Ea=2R.
JEE Main · 2020 · 05 Sep 2020 · Shift 2 · Single correct option