The reaction of NO with $\mathrm{N}_{2} \mathrm{O}_{4}$ at 250 K gives:

(C) $\mathrm{N}_{2} \mathrm{O}_{3}$

(A) $\mathrm{N}_{2} \mathrm{O}$

(D) $\mathrm{N}_{2} \mathrm{O}_{5}$

JEE Main · 2020 · 06 Sep 2020 · Shift 2 · p-Block Elements

The reaction of NO with

N_{2} O_{4}

at 250 K gives:

(A) $N_{2} O$
(B) $NO_{2}$
(C) $N_{2} O_{3}$ ✓ Correct
(D) $N_{2} O_{5}$

Answer: (C)

Solution

At the low temperature of

250 K

, nitric oxide combines with dinitrogen tetroxide to give the mixed oxide dinitrogen trioxide:

2 NO + N X_{2} O X_{4} - > 2 N X_{2} O X_{3}

. The product is

N X_{2} O X_{3}

JEE Main · 2020 · 06 Sep 2020 · Shift 2 · Single correct option

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