JEE Main · 2020 · 06 Sep 2020 · Shift 1 · Haloalkanes and Haloarenes

The major products of the following reaction are:

(A)(see structure)
(B)(see structure)
(C)(see structure)
(D)(see structure)
✓ Correct

Answer: (D)

Solution

Bromine adds across the carbon-carbon double bond by electrophilic addition. The alkene first forms a cyclic bromonium ion, which is then opened by bromide attacking from the opposite face, so the two bromine atoms finish anti to one another across the former double bond. Carrying this anti, trans addition through on the given substrate gives the vicinal dibromide with the two bromine atoms on opposite faces.

JEE Main · 2020 · 06 Sep 2020 · Shift 1 · Single correct option

Practise more: all JEE Main PYQs on Haloalkanes and Haloarenes →

More JEE Main questions on Haloalkanes and Haloarenes

The correct order of reactivity of $CH_{3} Br$ in methanol with the following nucleophiles is $F^{-}, I^{-}, C_{2} H_{5} O^{-}$ and $C_{6} H_{5} O^{-}$
JEE Main 2026View solution →
The correct order of the rate of reaction of the following reactants with nucleophile by $S_{N} 1$ mechanism is :
(Given : Structure I and II are rigid)
JEE Main 2026View solution →
The correct order of reactivity of the following benzyl halides towards reaction with KCN is:
JEE Main 2026View solution →
The correct order of the rate of the reaction for the following reaction with respect to nucleophiles is:
$CH_{3} Br + Nu^{Θ} ⟶ CH_{3} Nu + Br^{Θ}$
JEE Main 2026View solution →
Given below are four compounds:
(a) n-propyl chloride
(b) iso-propyl chloride
(c) sec-butyl chloride
(d) neo-pentyl chloride

Percentage of carbon in the one which exhibits optical isomerism is:
JEE Main 2026View solution →
Consider the following reaction :

$(i) NaNH_{2} (ii) ↓ - Br Y$

The product Y formed is :
JEE Main 2026View solution →