JEE Main · 2019 · 08 Apr 2019 · Shift 1 · Solid State

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Element 'B' forms ccp structure and 'A' occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The structure of bimetallic oxide is

(A) $A_{2} B_{2} O$
(B) $AB_{2} O_{4}$ ✓ Correct
(C) $A_{4} B_{2} O$
(D) $A_{2} BO_{4}$

Answer: (B)

Solution

In a ccp lattice of B there are

4

B atoms per unit cell, with

4

octahedral and

8

tetrahedral voids. A fills half the octahedral voids, giving

4 \times \frac{1}{2} = 2

atoms, and oxygen fills all the tetrahedral voids, giving

8

atoms. The unit-cell contents

A_{2} B_{4} O_{8}

reduce to the simplest formula

A B_{2} O_{4}

JEE Main · 2019 · 08 Apr 2019 · Shift 1 · Single correct option

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