The area (in sq. units) of the region A={(x,y):x2≤y≤x+2} is:
(A)631
(B)613
(C)29✓ Correct
(D)310
Answer: (C)
Solution
The curves y=x2 and y=x+2 meet where x2=x+2, that is (x−2)(x+1)=0, so between x=−1 and x=2 the line sits above the parabola. The area is ∫−12[(x+2)−x2]dx=[2x2+2x−3x3]−12=310−(−67)=627=29.
JEE Main · 2019 · 09 Apr 2019 · Shift 1 · Single correct option