JEE Main · 2019 · 11 Jan 2019 · Shift 2 · Practical and Analytical Chemistry

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25 mL of the given HCl solution requires 30 mL of 0.1 M sodium carbonate solution. What is the volume of this HCl solution required to titrate 30 mL of 0.2 M aqueous NaOH solution?

(A)25 mL✓ Correct
(B)75 mL
(C)50 mL
(D)12.5 mL

Answer: (A)

Solution

Use the law of equivalents. For

Na X_{2} CO X_{3}

with

HCl

(

Na X_{2} CO X_{3} + 2 HCl 2 NaCl + H X_{2} O + CO X_{2}

) the acid in

25 mL

carries

30 \times 0.1 \times 2 = 6

milli-equivalents, so

N_{HCl} = \frac{6}{25} = 0.24 N

. In the second titration

HCl + NaOH NaCl + H X_{2} O

, the acid needed for

30 mL

0.2 N

NaOH

V = \frac{30 \times 0.2}{0.24} = 25 mL

JEE Main · 2019 · 11 Jan 2019 · Shift 2 · Single correct option

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