JEE Main · 2019 · 12 Jan 2019 · Shift 2 · p-Block Elements

Chlorine on reaction with hot and concentrated sodium hydroxide gives :

(A) $Cl^{-}$ and $ClO_{3}^{-}$ ✓ Correct
(B) $Cl^{-}$ and $ClO^{-}$
(C) $ClO_{3}^{-}$ and $ClO_{2}^{-}$
(D) $Cl^{-}$ and $ClO_{2}^{-}$

Answer: (A)

Solution

Hot concentrated alkali drives chlorine to disproportionate all the way:

3 Cl X_{2} + 6 NaOH - > 5 NaCl + NaClO X_{3} + 3 H X_{2} O

. Chlorine is reduced to

Cl X^{-}

and at the same time oxidised to

ClO X_{3} X^{-}

(cold dilute alkali would stop instead at

Cl X^{-}

and

ClO X^{-}

JEE Main · 2019 · 12 Jan 2019 · Shift 2 · Single correct option

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