The major product in the following conversion is :
(A)(see structure)
(B)(see structure)
(C)(see structure)
(D)(see structure)✓ Correct
Answer: (D)
Solution
Adding HBr to the alkene in the presence of a peroxide proceeds by the radical route, so the bromine attaches anti-Markovnikov at the less substituted carbon of the side chain, while the phenolic −OH is left untouched. The product carries the bromo-substituted side chain with the free phenol.
JEE Main · 2019 · 12 Jan 2019 · Shift 2 · Single correct option