JEE Main · 2019 · 12 Jan 2019 · Shift 2 · Complex Numbers

WhatsApp Email
Let and be two complex numbers satisfying and . Then the minimum value of is :
  1. (A)0✓ Correct
  2. (B)
  3. (C)1
  4. (D)2

Answer: (A)

Solution

lies on the circle of radius about the origin, and on the circle of radius about , whose centre is distance from the origin. Because , the smaller circle sits exactly inside and touches the larger one internally, so the closest the two loci come is .

JEE Main · 2019 · 12 Jan 2019 · Shift 2 · Single correct option

More JEE Main questions on Complex Numbers

  1. If , then the value of is :
    JEE Main 2026View solution →
  2. Let z be the complex number satisfying and having maximum positive principal argument.
    Then is equal to:
    JEE Main 2026View solution →
  3. Let and . If , then m is
    JEE Main 2026View solution →
  4. Let . Then is equal to :
    JEE Main 2026View solution →
  5. Let be a set of complex numbers. Then is equal to:
    JEE Main 2026View solution →
  6. If , then is equal to
    JEE Main 2026View solution →