Phenol on treatment with $\mathrm{CO}_{2}$ in the presence of NaOH followed by acidification produces compound $X$ as the major product. $X$ on treatment with $\left(\mathrm{CH}_{3} \mathrm{CO}\right)_{2} \mathrm{O}$ in the presence of catalytic amount of $\mathrm{H}_{2} \mathrm{SO}_{4}$ produces :

JEE Main · 2018 · 08 Apr 2018 · Offline · Alcohols Phenols and Ethers

Phenol on treatment with

CO_{2}

in the presence of NaOH followed by acidification produces compound

X

as the major product.

X

on treatment with

(CH_{3} CO)_{2} O

in the presence of catalytic amount of

H_{2} SO_{4}

produces :

Answer: (B)

Phenol with

CO X_{2}

and

NaOH

followed by acidification is the Kolbe-Schmitt route to salicylic acid, so X is 2-hydroxybenzoic acid. Treating that phenolic

- OH

with acetic anhydride under a trace of acid acetylates it, and the product is acetylsalicylic acid, that is aspirin.

JEE Main · 2018 · 08 Apr 2018 · Offline · Single correct option