A mass 'm' is supported by a massless string wound around a uniform hollow cylinder of mass m and radius R. If the string does not slip on the cylinder, with what acceleration will the mass fall on release?
(A)65g
(B)g
(C)32g
(D)2g✓ Correct
Answer: (D)
Solution
Let the mass fall with acceleration a. For the mass, mg−T=ma. For the hollow cylinder the moment of inertia is I=mR2, and the torque from the string gives TR=IRa=mRa, so T=ma. Putting this into the first equation, mg−ma=ma, hence a=2g.
JEE Main · 2014 · 06 Apr 2014 · Offline · Single correct option