A metallic rod of length ' ℓ ' is tied to a string of length 2ℓ and made to rotate with angular speed ω on a horizontal table with one end of the string fixed. If there is a vertical magnetic field ' B ' in the region, the e.m.f. induced across the ends of the rod is:
(A)23Bωℓ2
(B)24Bωℓ2
(C)25Bωℓ2✓ Correct
(D)22Bωℓ2
Answer: (C)
Solution
The rod is not pinned at the axis; it hangs at the far end of a string of length 2ℓ, so as it sweeps round at angular speed ω it spans radial distances from 2ℓ to 3ℓ. A small element at radius x moves with speed ωx and contributes Bωxdx to the emf, so integrating across the rod, e=∫2ℓ3ℓBωxdx=2Bω[(3ℓ)2−(2ℓ)2]=2Bω(9ℓ2−4ℓ2)=25Bωℓ2.
JEE Main · 2013 · 07 Apr 2013 · Offline · Single correct option