JEE Main · 2011 · 10 Apr 2011 · Offline · Electromagnetic Induction

A boat is moving due east in a region where the earth's magnetic field is

5.0 \times 1 0^{- 5} NA^{- 1} m^{- 1}

due north and horizontal. The boat carries a vertical aerial 2 m long. If the speed of the boat is

1.50 ms^{- 1}

, the magnitude of the induced emf in the wire of aerial is :

(A)0.75 mV
(B)0.50 mV
(C)0.15 mV✓ Correct
(D)1 mV

Answer: (C)

Solution

As the vertical aerial moves east through the horizontal, north-pointing component of the field, the motional emf is

ε = B_{H} l v

. With

B_{H} = 5.0 \times 1 0^{- 5} T

l = 2 m

and

v = 1.5 m s^{- 1}

ε = 5.0 \times 1 0^{- 5} \times 2 \times 1.5 = 1.5 \times 1 0^{- 4} V = 0.15 mV

JEE Main · 2011 · 10 Apr 2011 · Offline · Single correct option

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