A triangular park is enclosed on two sides by a fence and on the third side by a straight river bank. The two sides having fence are of same length x. The maximum area enclosed by the park is
(A)23x2
(B)8x3
(C)21x2✓ Correct
(D)πx2
Answer: (C)
Solution
Let the two fenced sides, each of length x, meet at an angle θ, with the river forming the third side. The area of the triangle is A=21x2sinθ, in which only sinθ varies. Since sinθ is largest, equal to 1, when θ=2π, the greatest area that can be enclosed is A=21x2.
JEE Main · 2006 · 30 Apr 2006 · Offline · Single correct option