The major product obtained in the following reaction is: [PhCHBr-CH₂Ph treated with tBuOK — structure in source]
- (A)C₆H₅CH=CHC₆H₅ (trans-stilbene)✓ Correct
- (B)[structure - refer to source PDF]
- (C)C₆H₅CH(OtBu)CH₂C₆H₅
- (D)[structure - refer to source PDF]
Answer: (A)
Solution
undergoes E2 elimination with the strong, bulky base . Anti-periplanar loss of HBr forms the alkene, and the more stable, less hindered isomer predominates, giving -stilbene (trans-stilbene), .
JEE Main · 2017 · 02 Apr 2017 · Offline · Single correct option