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JEE Main · 2025 · 08 Apr 2025 · Shift 2 · Practical and Analytical Chemistry

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Match the LIST-I with LIST-II:
LIST-I (Reagent): A. Sodium bicarbonate solution B. Neutral ferric chloride C. Ceric ammonium nitrate D. Alkaline KMnO₄
LIST-II (Functional Group detected): I. Double bond/unsaturation II. Carboxylic acid III. Phenolic -OH IV. Alcoholic -OH
Choose the correct answer from the options given below:
  1. (A)A-II, B-III, C-IV, D-I✓ Correct
  2. (B)A-II, B-III, C-I, D-IV
  3. (C)A-III, B-II, C-IV, D-I
  4. (D)A-II, B-IV, C-III, D-I

Answer: (A)

Solution

Each reagent is a specific functional-group test. Sodium bicarbonate solution gives brisk effervescence of carbon dioxide only with a carboxylic acid. Neutral ferric chloride develops a violet or blue colour with a phenolic hydroxyl. Ceric ammonium nitrate produces a red colour with an alcoholic hydroxyl. Alkaline potassium permanganate, Baeyer's reagent, is decolourised by a carbon-carbon double bond, the test for unsaturation. The correct pairing is sodium bicarbonate with carboxylic acid, neutral ferric chloride with phenolic hydroxyl, ceric ammonium nitrate with alcoholic hydroxyl, and alkaline permanganate with unsaturation.

JEE Main · 2025 · 08 Apr 2025 · Shift 2 · Single correct option

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