Match List-I with List-II.
List-I (Mixture of Compounds):
A. Diethyl amine + Ethyl amine
B. Acetaldehyde + Acetone
C. Ethanol + Phenol
D. Benzoic acid + Cinnamic acid
List-II (Reagent used to distinguish):
I. Bromine water
II.
III. Neutral
IV. Ammonical silver nitrate
Choose the correct answer from the options given below:
List-I (Mixture of Compounds):
A. Diethyl amine + Ethyl amine
B. Acetaldehyde + Acetone
C. Ethanol + Phenol
D. Benzoic acid + Cinnamic acid
List-II (Reagent used to distinguish):
I. Bromine water
II.
III. Neutral
IV. Ammonical silver nitrate
Choose the correct answer from the options given below:
Answer: A → II, B → IV, C → III, D → I
Solution
A primary amine (ethylamine) gives the carbylamine reaction with chloroform and alcoholic KOH on heating, forming a foul-smelling isocyanide, whereas the secondary amine diethylamine does not, so that pair is told apart by . An aldehyde (acetaldehyde) gives a silver mirror with ammoniacal silver nitrate while the ketone acetone does not, so that pair is distinguished by ammoniacal silver nitrate. Phenol gives a violet colour with neutral but ethanol does not, separating that pair. Cinnamic acid contains a bond and decolourises bromine water, while benzoic acid does not, distinguishing that pair. The matching is A-II, B-IV, C-III, D-I.
JEE Main · 2026 · 02 Apr 2026 · Shift 1 · Match the columns