JEE Main · 2026 · 05 Apr 2026 · Shift 1 · Units & Measurement

L, C and R represents physical quantities inductance, capacitance and resistance respectively.

The dimensional formula

ML^{2} T^{- 4} A^{- 2}

corresponds to ______.

Answer: (A)

Solution

The dimensions are

[R] = M L^{2} T^{- 3} A^{- 2}

[L] = M L^{2} T^{- 2} A^{- 2}

(from

U = \frac{1}{2} L I^{2}

) and

[C] = M^{- 1} L^{- 2} T^{4} A^{2}

(from

Q = C V

). Their product is

[L C] = T^{2}

, so

L C

has the dimension of time

T

. Dividing,

[\frac{R}{L C}] = \frac{M L ^{2} T ^{- 3} A ^{- 2}}{T} = M L^{2} T^{- 4} A^{- 2}

, which matches the given formula. The quantity with dimensions

M L^{2} T^{- 4} A^{- 2}

\frac{R}{L C}

JEE Main · 2026 · 05 Apr 2026 · Shift 1 · Single correct option