JEE Main · 2026 · 05 Apr 2026 · Shift 1 · Biomolecules

Glucose closes into a cyclic hemiacetal that can adopt two arrangements at the newly formed stereocentre, giving the two anomers, so statement A is correct, and because these forms differ only in configuration at the anomeric carbon C-1, statement B is correct. The specific rotations are $+112^{\circ }$ for the $\alpha$ anomer and $+19^{\circ }$ for the $\beta$ anomer, the reverse of statement D, so statement D is wrong. The melting point of the $\beta$ anomer, about $150{}^{\circ }\mathrm{C}$, exceeds that of the $\alpha$ anomer, about $146{}^{\circ }\mathrm{C}$, contrary to statement C, so statement C is wrong. The $\alpha$ anomer crystallises from a concentrated solution at $303\mathrm{K}$ and the $\beta$ anomer from a hot solution at $371\mathrm{K}$, so statement E is correct. The correct statements are A, B and E.