JEE Main · 2026 · 06 Apr 2026 · Shift 1 · Elasticity & SHM

A particle is executing simple harmonic motion. Its amplitude is A and time period is 5 sec. The time required by it to move from

x = A

x = \frac{A}{2}

is ______ sec.

Answer: (C)

Solution

Measuring from the extreme position,

x = A cos (ω t)

. At

x = \frac{A}{2}

cos (ω t) = \frac{1}{2}

, so

ω t = \frac{π}{4}

. Thus

t = \frac{π /4}{ω} = \frac{π /4}{2 π / T} = \frac{T}{8} = \frac{5}{8}

s. The time taken is

\frac{5}{8}

JEE Main · 2026 · 06 Apr 2026 · Shift 1 · Single correct option