A current of 30 A each flows in opposite directions in two conducting wires, placed parallel to each other at a distance of 8 cm. The magnetic field at the mid point between the two wires is ______ μT. (4πμ0=10−7N/A2)
(A)30
(B)300✓ Correct
(C)150
(D)0.1
Answer: (B)
Solution
Currents in opposite directions produce fields that point the same way midway between the wires, so they add: B=2⋅2πrμ0I=πrμ0I, with r=4×10−2m. Then B=π×4×10−24π×10−7×30=3×10−4T=300μT.
JEE Main · 2026 · 06 Apr 2026 · Shift 2 · Single correct option