Consider two radiations of wavelengths : 1. $\lambda_{1}=2000$ Å 2. $\lambda_{2}=6000$ Å The ratio of the energies of these two radiations $\left(\frac{\mathrm{E}_{1}}{\mathrm{E}_{2}}\right)$ is ____. (Nearest integer)

JEE Main · 2026 · 08 Apr 2026 · Shift 2 · Atomic Structure

Consider two radiations of wavelengths :

The ratio of the energies of these two radiations

(\frac{E _{1}}{E _{2}})

is ____. (Nearest integer)

Answer: 3

The energy of a photon is

E = \frac{h c}{λ}

, so for fixed

h

and

c

the energy varies inversely with wavelength and

\frac{E _{1}}{E _{2}} = \frac{λ _{2}}{λ _{1}}

. Substituting,

\frac{E _{1}}{E _{2}} = \frac{6000}{2000} = 3

. The ratio of the energies is

3

JEE Main · 2026 · 08 Apr 2026 · Shift 2 · Integer answer