JEE Main · 2026 · 08 Apr 2026 · Shift 2 · Laws of Motion

A car moving with a speed of

54 km / h

takes a turn of radius 20 m. A simple pendulum is suspended from the ceiling of the car. Determine the angle made by the string of the pendulum with the vertical during the turning. (Take

g = 10 m / s^{2}

)

(A) $tan^{- 1} (0.5)$
(B) $tan^{- 1} (0.75)$
(C) $tan^{- 1} (1.125)$ ✓ Correct
(D) $tan^{- 1} (0.25)$

Answer: (C)

Solution

Converting the speed,

v = 54 \times \frac{5}{18} = 15 m/s

. As the car turns, the bob settles where the horizontal component of the string tension supplies the centripetal force while the vertical component balances gravity, so

tan θ = \frac{v ^{2}}{r g}

. Substituting,

tan θ = \frac{1 5 ^{2}}{20 \times 10} = \frac{225}{200} = 1.125

. The string makes an angle

tan^{- 1} (1.125)

with the vertical.

JEE Main · 2026 · 08 Apr 2026 · Shift 2 · Single correct option

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