Question

List-I contains various physical/chemical processes, and List-II contains combinations of changes in enthalpy $(\Delta \mathrm{H})$ and entropy $(\Delta \mathrm{S})$. Match each entry in List-I to appropriate entry in List-II, and choose the correct option. | List-I | | List-II | | |--------|---------|---------|---| | (P) | Physisorption | (1) | $\Delta \mathrm{H}>0$ and $\Delta \mathrm{S}>0$ | | (Q) | Diamond → Graphite | (2) | $\Delta \mathrm{H}<0$ and $\Delta \mathrm{S}<0$ | | (R) | Denuturation of protein | (3) | $\Delta \mathrm{H}<0$ and $\Delta \mathrm{S}=0$ | | (S) | Propene → Cyclopropane | (4) | $\Delta \mathrm{H}>0$ and $\Delta \mathrm{S}<0$ | | | | (5) | $\Delta \mathrm{H}<0$ and $\Delta \mathrm{S}>0$ |

Accepted Answer

(C) $\mathrm{P} \rightarrow 2 ; \mathrm{Q} \rightarrow 5 ; \mathrm{R} \rightarrow 1 ; \mathrm{S} \rightarrow 4$

Answer

(A) $\mathrm{P} \rightarrow 2 ; \mathrm{Q} \rightarrow 3 ; \mathrm{R} \rightarrow 5 ; \mathrm{S} \rightarrow 4$

Answer

(B) $\mathrm{P} \rightarrow 4 ; \mathrm{Q} \rightarrow 3 ; \mathrm{R} \rightarrow 5 ; \mathrm{S} \rightarrow 1$

Answer

(D) $\mathrm{P} \rightarrow 2 ; \mathrm{Q} \rightarrow 5 ; \mathrm{R} \rightarrow 1 ; \mathrm{S} \rightarrow 3$

JEE Advanced · 2026 · 17 May 2026 · Paper 1 · Chemical Thermodynamics

Solution

More JEE Advanced questions on Chemical Thermodynamics

List-I		List-II
(P)	Physisorption	(1)	$Δ H > 0$ and $Δ S > 0$
(Q)	Diamond → Graphite	(2)	$Δ H < 0$ and $Δ S < 0$
(R)	Denuturation of protein	(3)	$Δ H < 0$ and $Δ S = 0$
(S)	Propene → Cyclopropane	(4)	$Δ H > 0$ and $Δ S < 0$
		(5)	$Δ H < 0$ and $Δ S > 0$