An annular disk of mass M, inner radius a and outer radius b is placed on a horizontal surface with coefficient of friction μ, as shown in the figure. At some time, an impulse J0x^ is applied at a height h above the center of the disk. If h=hm then the disk rolls without slipping along the x-axis. Which of the following statement(s) is(are) correct ?
(A)For μ=0 and a→0,hm=b/2✓ Correct
(B)For μ=0 and a→b,hm=b✓ Correct
(C)For h=hm, the initial angular velocity does not depend on the inner radius a.✓ Correct
(D)For μ=0 and h=0, the wheel always slides without rolling.✓ Correct
Answer: (A), (B), (C), (D)
Solution
For rolling without slipping: v=ωR.
From impulse: J0=mv and J0hm=Icω.
Combining: hm=mRIc.
(A) For a→0: Ic=21mb2 and R=b, so hm=2b. ✓
(B) For a→b: Ic=mb2 and R=b, so hm=b. ✓
(C) Angular velocity ω=mRJ0, which depends only on R (outer radius), not on a. ✓
(D) For μ=0 and h=0: impulse acts at center of mass, producing only translation with no torque, so no rotation occurs — pure sliding. ✓
JEE Advanced · 2023 · 04 Jun 2023 · Paper 2 · One or more correct options