A solid sphere of mass 1kg and radius 1m rolls without slipping on a fixed inclined plane with an angle of inclination θ=30∘ from the horizontal. Two forces of magnitude 1N each, parallel to the incline, act on the sphere, both at distance r=0.5m from the center of the sphere, as shown in the figure. The acceleration of the sphere down the plane is ____ ms−2. (Take g=10ms−2.)
Answer: 2.86
Solution
Forces along the incline:
mgsin30°+1−1−f=ma
5−f=a
Torque about center of mass:
f×1−2(1×0.5)=Iα=52mr2×ra
f−1=52a
f=1+52a
Substituting:
5−a=1+52a
4=57a
a=720=2.86m/s2
JEE Advanced · 2022 · 28 Aug 2022 · Paper 1 · Numerical answer