JEE Advanced · 2022 · 28 Aug 2022 · Paper 1 · Practical and Analytical Chemistry

Consider the following reaction.

On estimation of bromine in 1.00 g of

R

using Carius method, the amount of AgBr formed (in g ) is ____.

[Given : Atomic mass of

H = 1, C = 12, O = 16, P = 31, Br = 80, Ag = 108

]

Answer: 1.5

Solution

From the reaction scheme, compound

R

is formed and contains 2 bromine atoms. The molecular formula of

R

C_{6} H_{4} Br_{2} O_{2}

with molar mass = 72 + 4 + 160 + 32 = 250 g/mol (approximately, based on the structure).

1.00 g of

R

\frac{1}{250}

mol.

Number of Br atoms =

2 \times \frac{1}{250} = \frac{2}{250}

mol.

Moles of AgBr formed =

\frac{2}{250}

mol.

Mass of AgBr =

\frac{2}{250} \times (108 + 80) = \frac{2}{250} \times 188 = 1.504

g ≈ 1.50 g.

JEE Advanced · 2022 · 28 Aug 2022 · Paper 1 · Numerical answer

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