JEE Advanced · 2021 · 03 Oct 2021 · Paper 2 · Alternating Current

In a circuit, a metal filament lamp is connected in series with a capacitor of capacitance

C μ F

across a 200 V, 50 Hz supply. The power consumed by the lamp is 500 W while the voltage drop across it is 100 V. Assume that there is no inductive load in the circuit. Take rms values of the voltages. The magnitude of the phase-angle (in degrees) between the current and the supply voltage is

φ

. Assume,

π 3 \approx 5

.

The value of

φ

is ____.

Answer: 60

Solution

From the previous question, we found:

V_{C} = 1003

V and

V_{R} = 100

V

The phase angle is given by:

tan ϕ = \frac{V _{C}}{V _{R}} = \frac{100 3}{100} = 3

Therefore:

ϕ = tan^{- 1} (3) = 6 0^{\circ}

φ = 60.00

JEE Advanced · 2021 · 03 Oct 2021 · Paper 2 · Numerical answer

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