Let be the origin and let be an arbitrary triangle. The point is such that
Then the triangle has as its
Then the triangle has as its
- (A)centroid
- (B)circumcentre
- (C)incentre
- (D)orthocenter✓ Correct
Answer: (D)
Solution
From the first equality:
This shows . Similarly, from the other equalities, we get and .
Since the lines from to each vertex are perpendicular to the opposite sides, is the orthocenter.
This shows . Similarly, from the other equalities, we get and .
Since the lines from to each vertex are perpendicular to the opposite sides, is the orthocenter.
JEE Advanced · 2017 · 21 May 2017 · Paper 2 · Single correct option