JEE Advanced · 2017 · 21 May 2017 · Paper 2 · Vector Algebra

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Let be the origin and let be an arbitrary triangle. The point is such that

Then the triangle has as its
  1. (A)centroid
  2. (B)circumcentre
  3. (C)incentre
  4. (D)orthocenter✓ Correct

Answer: (D)

Solution

From the first equality:





This shows . Similarly, from the other equalities, we get and .

Since the lines from to each vertex are perpendicular to the opposite sides, is the orthocenter.

JEE Advanced · 2017 · 21 May 2017 · Paper 2 · Single correct option

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