The circle C1:x2+y2=3, with centre at O, intersects the parabola x2=2y at the point P in the first quadrant. Let the tangent to the circle C1 at P touches other two circles C2 and C3 at R2 and R3, respectively. Suppose C2 and C3 have equal radii 23 and centres Q2 and Q3, respectively. If Q2 and Q3 lie on the y-axis, then
(A)Q2Q3=12✓ Correct
(B)R2R3=46✓ Correct
(C)area of the triangle OR2R3 is 62✓ Correct
(D)area of the triangle PQ2Q3 is 42
Answer: (A), (B), (C)
Solution
Solving x2+y2=3 and x2=2y gives 2y+y2=3, so y2+2y−3=0, thus y=1 (first quadrant). Then x=2, so P(2,1).
Tangent at P to circle: 2x+y=3.
Centres Q2(0,α2) and Q3(0,α3) on y-axis with radius 23.
Distance from centre to tangent equals radius:
3∣α−3∣=23⇒∣α−3∣=6
So α=9 or α=−3. Thus Q2(0,−3) and Q3(0,9).
(A)Q2Q3=12. True.
(B) Length of transverse common tangent: R2R3=(Q2Q3)2−(r2+r3)2=144−48=96=46. True.
(C) Perpendicular distance from O to tangent: 33=3. Area =21⋅46⋅3=62. True.
(D) Area of △PQ2Q3=21⋅12⋅2=62. False (source says 42 is wrong).
JEE Advanced · 2016 · 22 May 2016 · Paper 1 · One or more correct options