$\mathrm{Fe}^{3+}$ is reduced to $\mathrm{Fe}^{2+}$ by using

(A) $\mathrm{H}_{2}\mathrm{O}_{2}$ in presence of NaOH; (B) $\mathrm{Na}_{2}\mathrm{O}_{2}$ in water

(C) $\mathrm{H}_{2}\mathrm{O}_{2}$ in presence of $\mathrm{H}_{2}\mathrm{SO}_{4}$

(D) $\mathrm{Na}_{2}\mathrm{O}_{2}$ in presence of $\mathrm{H}_{2}\mathrm{SO}_{4}$

Hydrogen — JEE Advanced · 2015 · 24 May 2015 · Paper 1 Question with Solution

Fe^{3 +}

is reduced to

Fe^{2 +}

by using

Answer: (A), (B)

H_{2} O_{2}

can act as both oxidizing and reducing agent depending on conditions.

(A) Correct: In basic medium (NaOH),

H_{2} O_{2}

acts as a reducing agent and reduces

Fe^{3 +}

Fe^{2 +}

.

(B) Correct:

Na_{2} O_{2}

in water produces

H_{2} O_{2}

and NaOH (basic medium), which reduces

Fe^{3 +}

.

(C) Incorrect: In acidic medium (

H_{2} SO_{4}

H_{2} O_{2}

acts as an oxidizing agent.

(D) Incorrect:

Na_{2} O_{2}

in acidic medium acts as an oxidizing agent.

Correct answers: (A) and (B).

JEE Advanced · 2015 · 24 May 2015 · Paper 1 · One or more correct options