Charges Q,2Q and 4Q are uniformly distributed in three dielectric solid spheres 1, 2 and 3 of radii R/2,R and 2R, respectively, as shown in figure. If magnitudes of the electric fields at point P at a distance R from the center of spheres 1, 2 and 3 are E1,E2 and E3 respectively, thenSphere 1Sphere 2Sphere 3
(A)E1>E2>E3
(B)E3>E1>E2
(C)E2>E1>E3✓ Correct
(D)E3>E2>E1
Answer: (C)
Solution
For sphere 1: Point P is outside (at distance R from center, radius R/2), so E1=R2kQ.
For sphere 2: Point P is on the surface (at distance R from center, radius R), so E2=R2k(2Q)=R22kQ.
For sphere 3: Point P is inside (at distance R from center, radius 2R). For a uniformly charged sphere, the field inside at distance r is E=R3kQr, so E3=(2R)3k(4Q)R=8R34kQR=2R2kQ.
Comparing: E2=R22kQ, E1=R2kQ, E3=2R2kQ.
Therefore, E2>E1>E3.
JEE Advanced · 2014 · 25 May 2014 · Paper 2 · Single correct option