A small block of mass of 0.1 kg lies on a fixed inclined plane PQ which makes an angle θ with the horizontal. A horizontal force of 1 N acts on the block through its center of mass as shown in the figure. The block remains stationary if ( take g=10m/s2 )
(A)θ=45∘✓ Correct
(B)θ>45∘ and a frictional force acts on the block towards P.
(C)θ>45∘ and a frictional force acts on the block towards Q.✓ Correct
(D)θ<45∘ and a frictional force acts on the block towards Q.
Answer: (A), (C)
Solution
For equilibrium along the incline: mgsinθ=1cosθ when θ=45∘ (no friction needed). For θ>45∘, mgsinθ>1cosθ, so friction acts upward (towards P). For θ<45∘, mgsinθ<1cosθ, so friction acts downward (towards Q). Options (A) and (C) are correct.
JEE Advanced · 2012 · 08 Apr 2012 · Paper 1 · One or more correct options