JEE Advanced · 2012 · 08 Apr 2012 · Paper 1 · Solid State

WhatsApp Email
A compound has cubic close packing (ccp) arrangement of X. Its unit cell structure is shown below. The empirical formula of the compound is
  1. (A)MX
  2. (B)✓ Correct
  3. (C)
  4. (D)

Answer: (B)

Solution

From the unit cell structure: X atoms are at corners (8 × 1/8 = 1) and face centers (6 × 1/2 = 3), giving a total of X = 1 + 3 = 4. M atoms are at edge centers (4 × 1/4 = 1) and body center (1), giving a total of M = 1 + 1 = 2. The unit cell formula is , which simplifies to the empirical formula .

JEE Advanced · 2012 · 08 Apr 2012 · Paper 1 · Single correct option

More JEE Advanced questions on Solid State

  1. The density (in ) of the metal which forms a cubic close packed (ccp) lattice with an axial distance (edge length) equal to 400 pm is ____.

    Use: Atomic mass of metal = 105.6 amu and Avogadro's constant
    JEE Advanced 2025View solution →
  2. In a metal deficient oxide sample, ( and are metals), is present in both +2 and +3 oxidation states and is in +3 oxidation state. If the fraction …
    JEE Advanced 2024View solution →
  3. Atoms of metals , and z form face-centred cubic (fcc) unit cell of edge length , body-centred cubic (bcc) unit cell of edge length , and simple cubic unit cell of edge length …
    JEE Advanced 2023View solution →
  4. Atom X occupies the fcc lattice sites as well as alternate tetrahedral voids of the same lattice. The packing efficiency (in %) of the resultant solid is closest to
    JEE Advanced 2022View solution →
  5. For the given close packed structure of a salt made of cation X and anion Y shown below (ions of only one face are shown for clarity), the packing fraction is approximately (packing fraction = )
    JEE Advanced 2021View solution →
  6. The cubic unit cell structure of a compound containing cation M and anion X is shown below. When compared to the anion, the cation has smaller ionic radius. Choose the correct statement(s).
    JEE Advanced 2020View solution →