JEE Advanced · 2011 · 10 Apr 2011 · Paper 2 · Solid State

The number of hexagonal faces that are present in a truncated octahedron is

Answer: 8

Solution

A truncated octahedron is an Archimedean solid formed by truncating (cutting off) the corners of a regular octahedron.

When an octahedron (8 triangular faces, 6 vertices) is truncated:

Each of the 6 vertices becomes a square face
Each of the 8 original triangular faces becomes a hexagonal face

Therefore, a truncated octahedron has:

8 hexagonal faces
6 square faces
Total: 14 faces

The answer is 8.

JEE Advanced · 2011 · 10 Apr 2011 · Paper 2 · Integer answer

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