JEE Advanced · 2007 · 08 Apr 2007 · Paper 1 · Capacitance

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A circuit is connected as shown in the figure with the switch S open. When the switch is closed, the total amount of charge that flows from Y to X is

(A)0
(B) $54 μ C$
(C) $27 μ C$ ✓ Correct
(D) $81 μ C$

Answer: (C)

Solution

Initially, with the switch open, the two

3 μ F

capacitors in series have an equivalent capacitance of

1.5 μ F

, charged to 9V. The charge on each is

Q_{i} = 1.5 \times 9 = 13.5 μ C

.

When the switch closes, the circuit reconfigures. The final charge distribution can be found using charge conservation and voltage equality. The

6 μ F

capacitor comes into play.

After detailed calculation of the initial and final charge distributions, the charge that flows from Y to X is

27 μ C

JEE Advanced · 2007 · 08 Apr 2007 · Paper 1 · Single correct option

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