Match gases under specified conditions listed in Column I with their properties/laws in Column II. Indicate your answer by darkening the appropriate bubbles of the 4 × 4 matrix given in the ORS.
| Column I | Column II |
|---|---|
| (A) hydrogen gas (P=200 atm, T=273 K) | (p) compressibility factor ≠ 1 |
| (B) hydrogen gas (P ~ 0, T=273 K) | (q) attractive forces are dominant |
| (C) (P=1 atm, T=273 K) | (r) PV=nRT |
| (D) real gas with very large molar volume | (s) P(V-nb)=nRT |
Answer: A → I, A → IV, B → III, C → I, C → II, D → I, D → IV
Solution
(A) Hydrogen at high pressure (200 atm): Compressibility factor Z ≠ 1 due to significant repulsive forces. The van der Waals equation reduces to at high pressure. Matches: p, s.
(B) Hydrogen at very low pressure (P ~ 0): Behaves ideally, Z = 1, follows ideal gas law . Matches: r.
(C) at 1 atm and 273 K: Shows deviation from ideal behavior (Z ≠ 1) due to significant attractive intermolecular forces. Matches: p, q.
(D) Real gas with very large molar volume: At very large volumes, repulsive forces dominate, Z ≠ 1, and the equation approximates to . Matches: p, s.
(B) Hydrogen at very low pressure (P ~ 0): Behaves ideally, Z = 1, follows ideal gas law . Matches: r.
(C) at 1 atm and 273 K: Shows deviation from ideal behavior (Z ≠ 1) due to significant attractive intermolecular forces. Matches: p, q.
(D) Real gas with very large molar volume: At very large volumes, repulsive forces dominate, Z ≠ 1, and the equation approximates to . Matches: p, s.
JEE Advanced · 2007 · 08 Apr 2007 · Paper 1 · Match the columns