(A) $\mathrm{HOCl}+\mathrm{H}_{2} \mathrm{O}_{2} \rightarrow \mathrm{H}_{3} \mathrm{O}^{+}+\mathrm{Cl}^{-}+\mathrm{O}_{2}$ (B) $\mathrm{I}_{2}+\mathrm{H}_{2} \mathrm{O}_{2}+2 \mathrm{OH}^{-} \rightarrow 2 \mathrm{I}^{-}+2 \mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2}$ Choose the correct option.

(C) $\mathrm{H}_{2} \mathrm{O}_{2}$ acts as reducing agent in equations (A) and (B).

(A) $\mathrm{H}_{2} \mathrm{O}_{2}$ act as oxidizing and reducing agent respectively in equations (A) and (B).

(B) $\mathrm{H}_{2} \mathrm{O}_{2}$ acts as oxidizing agent in equations (A) and (B).

(D) $\mathrm{H}_{2} \mathrm{O}_{2}$ acts as reducing and oxidising agent respectively in equation (A) and (B).

JEE Main · 2021 · 24 Feb 2021 · Shift 1 · Hydrogen

(A)

HOCl + H_{2} O_{2} \to H_{3} O^{+} + Cl^{-} + O_{2}

(B)

I_{2} + H_{2} O_{2} + 2 OH^{-} \to 2 I^{-} + 2 H_{2} O + O_{2}

Choose the correct option.

(A) $H_{2} O_{2}$ act as oxidizing and reducing agent respectively in equations (A) and (B).
(B) $H_{2} O_{2}$ acts as oxidizing agent in equations (A) and (B).
(C) $H_{2} O_{2}$ acts as reducing agent in equations (A) and (B).✓ Correct
(D) $H_{2} O_{2}$ acts as reducing and oxidising agent respectively in equation (A) and (B).

Answer: (C)

To determine whether

H X_{2} O X_{2}

acts as an oxidizing or reducing agent, we examine the change in oxidation state of oxygen and whether

O X_{2}

is liberated.

When

H X_{2} O X_{2}

acts as a reducing agent, it is oxidized and liberates

O X_{2}

H X_{2} O X_{2} 2 H X^{+} + O X_{2} + 2 e X^{-}

In both reactions (A) and (B):

Here,

H X_{2} O X_{2}

is oxidized to

O X_{2}

, so it acts as a reducing agent.

Reaction (B): $I X_{2} + H X_{2} O X_{2} + 2 OH X^{-} 2 I X^{-} + 2 H X_{2} O + O X_{2}$

Here,

H X_{2} O X_{2}

is oxidized to

O X_{2}

, so it acts as a reducing agent.

In both equations,

H X_{2} O X_{2}

liberates

O X_{2}

, confirming that it acts as a reducing agent in both reactions.

JEE Main · 2021 · 24 Feb 2021 · Shift 1 · Single correct option