In the above chemical reaction sequence "A" and " B " respectively are :
(A)O3,Zn/H2O and NaOH(alc.)/I2✓ Correct
(B)H2O,H+and NaOH(alc.)/I2
(C)H2O,H+and KMnO4
(D)O3,Zn/H2O and KMnO4
Answer: (A)
Solution
Step 1 (A): ozonolysis of the alkene — O3 followed by reductive work-up with Zn/H2O — cleaves the C=C double bond to give the dialdehyde shown. Step 2 (B): the terminal methyl ketone-type carbon undergoes the iodoform reaction with NaOH(alc.)/I2, converting the CH3CO− group to CHI3 and a carboxylate. So A=O3,Zn/H2O and B=NaOH(alc.)/I2.
JEE Main · 2024 · 04 Apr 2024 · Shift 2 · Single correct option