A coil of area A and N turns is rotating with angular velocity ω in a uniform magnetic field B about an axis perpendicular to B. Magnetic flux φ and induced emf ε across it, at an instant when B is parallel to the plane of coil, are :
(A)φ=AB,ε=0
(B)φ=0,ε=NABω✓ Correct
(C)φ=0,ε=0
(D)φ=AB,ε=NABω
Answer: (B)
Solution
For a coil of area A and N turns rotating with angular velocity ω about an axis perpendicular to a uniform field B, the angle between the normal to the coil and B at time t is ωt (taking t=0 when the normal is along B). The flux through the coil is
ϕ=NBAcos(ωt)
and the induced emf is
ε=−dtdϕ=NBAωsin(ωt)
When B is parallel to the plane of the coil, the normal to the coil is perpendicular to B, so ωt=π/2. At this instant
ϕ=NBAcos(π/2)=0,ε=NBAωsin(π/2)=NBAω
JEE Main · 2025 · 29 Jan 2025 · Shift 1 · Single correct option