JEE Main · 2025 · 24 Jan 2025 · Shift 1 · Hydrocarbons

The product (A) formed in the following reaction sequence is :

Answer: (B)

Solution

C H_{3} - C \equiv C H

undergoes Markovnikov hydration under

H g^{2 +} / H_{2} S O_{4}

(oxymercuration–reduction pattern) to give the ketone

C H_{3} - C O - C H_{3}

(acetone).

Addition of

H C N

to the ketone carbonyl gives the cyanohydrin

C H_{3} - C (O H) (C N) - C H_{3}

.

Reduction of the nitrile with

H_{2} / N i

converts

- C N

- C H_{2} N H_{2}

while leaving the tertiary alcohol untouched, giving the final product

H O - C (C H_{3})_{2} - C H_{2} - N H_{2}

— 2-amino-2-methylpropan-1-ol.

JEE Main · 2025 · 24 Jan 2025 · Shift 1 · Single correct option