JEE Main · 2024 · 04 Apr 2024 · Shift 2 · Elasticity & SHM

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In simple harmonic motion, the total mechanical energy of given system is E . If mass of oscillating particle P is doubled then the new energy of the system for same amplitude is :

(A) $\frac{E}{2}$
(B)E✓ Correct
(C) $E 2$
(D)2E

Answer: (B)

Solution

Total mechanical energy of an oscillator is

E = \frac{1}{2} k A^{2}

, where

k

is the restoring-force (spring) constant — a property of the spring, not of the oscillating mass. If the amplitude

A

is unchanged and

k

is unchanged (only the mass on the spring changes), the total energy stays the same,

E

JEE Main · 2024 · 04 Apr 2024 · Shift 2 · Single correct option

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